Hypergeometric Distribution

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<LearnHypergeometricDistribution />

Αποτέλεσμα

For population size N = , Number of successes r = and number of draws n = we get

P (X = x) = \frac{(\binom{r}{x}) (\binom{N - r}{n - x})}{(\binom{N}{n})} = \frac{(\binom{5}{x}) (\binom{5}{2 - x})}{(\binom{10}{2})}

Evaluated at x = we get

P (X = x) = \frac{(\binom{5}{0}) (\binom{5}{2 - 0})}{(\binom{10}{2})} \approx 0.2222

Population size:

Number of successes:

Number of draws / trials:

x0:
03

P (X \leq 0) = 0.2222

Population size:

Number of successes:

Number of draws / trials:

x0:
03

P (X > 0) = 0.7778

Population size:

Number of successes:

Number of draws / trials:

x0:
03

x1:
03

P (0 \leq X \leq 1) = 0.7778